# What is the molarity of a NaNO3 solution made by diluting 250mL of a 1.60M solution to a final volume of 400.mL?

Looking to double check my work. I'm a new Chemistry student but I believe the answer is .96M.

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- Trevor HLv 75 months agoFavorite Answer
Whenever you have a dilution problem like this use the dilution equation:

M1V1 = M2V2

M1*400mL = 1.60M * 250mL

M1 = 1.60M * 250mL / 400mL

M1 = 1.00M

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