A fair coin is tossed 6 times. Compute the probability of tossing 6 heads in a row.?

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  • 6 months ago

    A fair coin is tossed 6 times.

    Compute the probability of tossing 6 heads in a row.

    Probability of getting 6 heads in a row: 1/2^6 = 1/64

  • 6 months ago

    P(6 heads) = 1/64 answer//

  • 6 months ago

    (1/2) (1/2) (1/2) (1/2) (1/2) (1/2) = (1/2)^6

  • 6 months ago

    p(6 heads in a row) =

    (1/2)^6 = 1/64

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  • Anonymous
    6 months ago

    1 in 64 is the chance.

  • 6 months ago

    P = 1/ 2^6 = 1/64

  • 6 months ago

    Total number of possible outcomes is 2^6 which is 64

    There is only one way to get 6 heads.

    The probability of tossing 6 heads in a row is 1/64

    Things would get more complicated somewhat if less than 6 heads were involved, because permutations and/or combinations would be brought in.

  • A.J.
    Lv 7
    6 months ago

    1 in 2, or 50% on each toss to get a head assuming no stand-on-edge or coin down the sewer tosses.

    0.5 raised to the 6th power

    0.5 x 0.5 x 0.5 x 0.5 x 0.5 x 0.5

    or

    1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2

    1/64 or 0.015625 or 1.5625%

  • 6 months ago

    One chance in 64.

  • 6 months ago

    1/2^6.

    Toss it once, the odds of heads is 1/2

    Toss it twice and the odds of two head is 1/4 (1/2*1/2)

    Toss it three times and the odds of three heads is 1/8 (1/2*1/2*1/2)

    You can see that the odds of all heads is (1/2)^n where n is the number of coin tosses.

    EDIT - It's not 1/2^6, it's (1/2)^6. Sorry about that.

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