Anonymous

# Answer to this question?

How many calories are lost or gained to melt 45.0g of ice at 0oC?

3.6 cal

3.6 x 103 cal

1.8 cal

80. cal

0.56 cal

### 3 Answers

Relevance

- pisgahchemistLv 76 months ago
Heat of fusion ....

q = mHf = 45.0g x 79.9 cal/g = 3596 cal

........ round to three significant digits: .... 3.60x10^3 cal

Chances are someone used 80. cal/g rather than 79.9 cal/g. Therefore, the answer would only be to two significant digits, which is why 3.6x10^3 cal is your choice.

- Roger the MoleLv 76 months ago
The heat of fusion of ice is 80. cal/g.

(80. cal/g) x (45.0 g) = 3600 cal = 3.6 x 10^3 cal

So choose your second answer.

- billrussell42Lv 76 months ago
heat of fusion of ice is 334 kJ/kg = 334 J/g

45 g x 334 J/g = 15030 J

converting, that is 3590 cal

none of your answers are even close.

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I realize that, but the problem listed "3.6 x 103" Not 3.6 x 10^3

there is a huge difference between 10^3 = 1000 and 103=103

I realize he left out a "^", but .. not my job to correct typing mistakes, specially when it's not obvious.