Answer to this question?
How many calories are lost or gained to melt 45.0g of ice at 0oC?
3.6 x 103 cal
- pisgahchemistLv 76 months ago
Heat of fusion ....
q = mHf = 45.0g x 79.9 cal/g = 3596 cal
........ round to three significant digits: .... 3.60x10^3 cal
Chances are someone used 80. cal/g rather than 79.9 cal/g. Therefore, the answer would only be to two significant digits, which is why 3.6x10^3 cal is your choice.
- Roger the MoleLv 76 months ago
The heat of fusion of ice is 80. cal/g.
(80. cal/g) x (45.0 g) = 3600 cal = 3.6 x 10^3 cal
So choose your second answer.
- billrussell42Lv 76 months ago
heat of fusion of ice is 334 kJ/kg = 334 J/g
45 g x 334 J/g = 15030 J
converting, that is 3590 cal
none of your answers are even close.