1. An electric heater takes 1.48 kW from a voltage source of 220V. Find the resistance of the heater?

3 Answers

Relevance
  • 5 months ago

    Power = Volts²/R so R = Volts²/Power = 220²/1480 = 32.7Ω or about 33Ω

  • 5 months ago

    =E^2/P = (220*220)/1480= 32.7027 Ω

  • 5 months ago

    *** 32.7 OHM !!!!!

Still have questions? Get your answers by asking now.