.210 moles of a diatomic gas are in a piston the gas dos 185J of work while 390 of heat are added what is the change in temperature?
- DylanLv 69 months agoFavorite Answer
For diatomic ideal gas
U = 5/2 nRT (should be Delta on U and T)
U = Q - W
T = (Q-W)/(5/2 nR)
= (390-185)/(5/2 0.21*3.814)
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