# you throw a stone straight down. the stone starts with a velocity of 54 feet per second down. it leaves the sling 326 feet above the ground?

Update:

i need the equation for algebra

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• Adding a question mark does not make a question.

ASKING a question makes a question.

What did you hope to find?

AN equation could be as simple as

h = 326

or

v = -54

These are both equations.

as is h = vt + 1/2 g t^2

or v^2 = u^2 + 2gh

v = u + gt

All of these are equations that MIGHT be relevant.

And I could think of so many more.

To ask a question you need to have some clear idea of what it is that you need to find.

• There are two numbers that you can find. They are the stone’s velocity just before it hits the ground and time the stone is moving. The acceleration is 32 ft/s^2. Use the following equation to determine the stone’s velocity just before it hits the ground.

vf^2 = vi^2 + 2 * a * d

vf^2 = 54^2 + 2 * 32 * 326

vf = √23,780

This is approximately 154 ft/s. Use the following equation to determine the time.

vf = vi + a * t

√23,780 = 54 + 32 * t

t = (√23,780 – 54) ÷ 32

This is approximately 3.13 seconds. If you use a slightly different number for the acceleration, your answers will be slightly different. I hope this is helpful for you.

• It depends on what you are trying to find...i)the final velocity (v) or ii) the time it takes to reach the ground (t)

i) v^2 = u^2 + 2aS

ii) S = ut + at^2/2

• The stone's height above impact point is given by y(t) = h - Ut - 1/2 gt^2; where h = 326 ft, U = 54 fps, and g = 32.2 ft/s^2. To solve for t = ? time to impact, we set y(t) = 0 and solve the quadratic eqn.