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- mizooLv 78 months agoFavorite Answer
angle BCE = angle BCA + angle ACE

Let's find angle BCA and angle ACE:

angle ACE:

Arc AEC = 180

Arc CE + Arc AE = 180

50 + Arc AE = 180

Arc AE = 130

Angle ACE = 1/2 * Arc AE

Angle ACE = 1/2 * 130

Angle ACE = 65

angle BCA:

AB = BC => ABC is a Equilateral triangle

=> angle BCA = 45

angle BCE = 45° + 65°

angle BCE = 110°

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