In a Broadway performance, an 84.5-kg actor swings from a R = 4.35-m-long cable that is horizontal when he starts. At the bottom of his arc?

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In a Broadway performance, an 84.5-kg actor swings from a R = 4.35-m-long cable that is horizontal when he starts. At the bottom of his arc, he picks up his 55.0-kg costar in an inelastic collision. What maximum height do they reach after their upward swing?

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  • Anonymous
    6 months ago
    Best Answer

    Just prior to collision,

    v = √(2gh) = √(2 * 9.8m/s² * 4.35m) = 9.23 m/s

    conserve momentum during the collision:

    84.5kg * 9.23m/s + 55.0kg * 0m/s = (84.5 + 55.0)kg * V

    and so the post-collision momentum is

    V = 5.59 m/s

    H = V² / 2g = (5.59m/s)² / 19.6m/s² = 1.60 m

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