At each corner of a square of side there are point charges of magnitude Q, 2Q, 3Q, and 4Q (Figure 1).?

Determine the Magnitude of the force on the charge 2Q?

Determine the Direction of the force on the charge 2Q?

Attachment image

1 Answer

Relevance
  • 8 months ago
    Favorite Answer

    From Q, the force = k* Q*2Q/L² at 0°

    From 4Q, the force = k*4Q*2Q/2L² at 45°

    From 3Q, the force = k*3Q*2Q/L² at 90°

    Sum the horizontal components:

    (k*Q²/L²)(2*cos0+4*cos45+6*cos90) = 4.34e10*Q²/L²

    Sum the vertical components:

    (k*Q²/L²)(2*sin0+4*sin45+6*sin90) = 7.93e10*Q²/L²

    √(4.34²+7.93²) *1e10 *Q²/L² = 9e10 *Q²/L² at arctan(7.93/4.34) = 61.3°

Still have questions? Get your answers by asking now.