# Physics rotation help?

A star has a mass of 1.06 x 1030 kg and is moving in a circular orbit about the center of its galaxy. The radius of the orbit is 3.6 x 104 light-years (1 light-year = 9.5 x 1015 m), and the angular speed of the star is 1.1 x 10-15 rad/s. (a) Determine the tangential speed of the star. (b) What is the magnitude of the net force that acts on the star to keep it moving around the center of the galaxy?

### 2 Answers

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- oubaasLv 77 months agoBest Answer
r = 9.5*3.6*10^19 = 3.42*10^20 m

ω = 1.1*10^-15 rad/sec

tangential speed Vt = ω*r = 3.42*1.1*10^5 = 3.76*10^5 m/sec = 376 km/sec

g = Vt^2/r = 3.76^2*10^10/(3.42*10^20) = 4.13*10^-10 m/sec^2

F = g*Ms = 4.13*1.06*10^(30-10) = 4.38*10^20 N

- Anonymous7 months ago
A. V = ω*r = 1.1*10^-15*(3.6*10^4*9.5*10^15) = (solve for this)

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