Physics rotation help?

A star has a mass of 1.06 x 1030 kg and is moving in a circular orbit about the center of its galaxy. The radius of the orbit is 3.6 x 104 light-years (1 light-year = 9.5 x 1015 m), and the angular speed of the star is 1.1 x 10-15 rad/s. (a) Determine the tangential speed of the star. (b) What is the magnitude of the net force that acts on the star to keep it moving around the center of the galaxy?

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  • oubaas
    Lv 7
    7 months ago
    Best Answer

    r = 9.5*3.6*10^19 = 3.42*10^20 m

    ω = 1.1*10^-15 rad/sec

    tangential speed Vt = ω*r = 3.42*1.1*10^5 = 3.76*10^5 m/sec = 376 km/sec

    g = Vt^2/r = 3.76^2*10^10/(3.42*10^20) = 4.13*10^-10 m/sec^2

    F = g*Ms = 4.13*1.06*10^(30-10) = 4.38*10^20 N

  • Anonymous
    7 months ago

    A. V = ω*r = 1.1*10^-15*(3.6*10^4*9.5*10^15) = (solve for this)

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