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# A sample of 2.88 grams of ice is at -10.0 ºC. How much energy is required in calories to heat the sample to 169 ºC?

A sample of 2.88 grams of ice is at -10.0 ºC. How much energy is required in calories to heat the sample to 169 ºC?

The following values may be of use:

Specific heat of ice = 0.48 cal/(g ºC)

Heat of fusion = 80. cal/g

specific heat of water = 1.00 cal/(g ºC)

Heat of vaporization = 540. cal/g

specific heat of steam = 0.48 cal/(g ºC)

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- Anonymous1 year agoFavorite Answer
An excellent example off Youtube. Just replace their numbers with your numbers

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