Alice asked in Science & MathematicsMathematics · 8 months ago

# In an experiment Jim flips a fair coin and then rolls a fair die. What is the probability he gets a head and a three?

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• 8 months ago

(1/2) * (1/6) = 1/12

• 8 months ago

P(head & 3) = (1/2)(1/6) = 1/12 answer//

• geezer
Lv 7
8 months ago

Wow .. someone really doesn't inderstand how to work out a probibility.

All those thumbs down !

A coin has two sides .. so the probability of getting a head is 1 in 2

A coin has six sides .. so the probability of getting a three is 1 in 6

So .. the probability of of getting both is 1 in 12 ..... (1x1=1 ... 2x6=12)

• sepia
Lv 7
8 months ago

In an experiment Jim flips a fair coin and then rolls a fair die.

What is the probability he gets a head and a three?

7 : 12

• C
Lv 5
8 months ago

What is important that NO ONE is telling you is that a flipping a coin and rolling a die are INDEPENDENT EVENTS. So the Law of Multiplication for Independent Events is: P( A and B) = P(A) * P(B), where A is the first event and B is the second event.

• Como
Lv 7
8 months ago

:-

P ( head and three) = (1/2) (1/6) = 1/12

• Mike G
Lv 7
8 months ago

P = 1/2 * 1/6 = 1/12

• ?
Lv 7
8 months ago

P (Head) = 1/2

P (3) = 1/6

P (Head) AND P (3) = P (Head) • P (3)

.................................= 1/2 • 1/6

.................................= 1/12.....................ANS

• 8 months ago

1/6 X 1/2 = .0833%

• 8 months ago

The probability of heads is 1/2

The probability of rolling three is 1/6

1/2 * 1/6

= 1/12