Chem 1! For a particular reaction, ΔH = -14.20 kJ/mol and ΔS = -198.5 J/(mol·K). Calculate ΔG for this reaction at 298 K.?
I got -44.953 and I've redone the calculations several times and it's still wrong.
- FernLv 710 months ago
Delta G = -14.20 kJ/mole - 298(-0.198.5 kJ/moleK
Delta G = -14.20 - (-59.15)
Delta G = -14.20 + 59.15
Delta G = +44.953 kJ
Answer should be +44.95 kJ, not -44.95 kJ
- Kt SkycatLv 710 months ago
Negative 43. 953?!? OH NO! YOU CREATED A BLACK HOOOOOOOOOOOOOOOOOOOOOOOOOOOOLLLLE!.............. or you have a dead battery (Sorry, I never took chemistry, I took anatomy instead. Just offering some humor during your hectic homework!)