GMAT Math question help?
Someone explain to me answer, it's 132.
How many organizational structures can be formed that consist of Division A; at least one of Divisions B and C; at least two of Divisions D, E, and F; and at least two of Divisions G, H, J, and K?
- Mike GLv 71 year ago
S = Possible number of structures
S = 1*[2C1+2C2]*[3C2+3C3]*[4C2+4C3+4C4]
S = 1*[2+1]*[3+1]*[6+4+1]
S = 1*3*4*11 = 132
- az_lenderLv 71 year ago
Three possibilities: B, C, BC;
Four possibilities: DE, DF, EF, DEF;
Eleven possibilities: GH, GJ, GK, HJ, HK, JK, GHJ, GHK, GJK, HJK, GHJK.
3 x 4 x 11 = 132.
- L. E. GantLv 71 year ago
A ==> 1
B or C or (B AND C) ==> 3 choices
DE or DF or EF or (D AND E AND F) = 4 choices
GH or GJ or GK or HJ or HK or JK or (Not G) or (Not H) or (Not J) or (not K) or (GHJK) = 11
so 1 * 3 * 4 * 11 = 132