Sally asked in Science & MathematicsPhysics · 11 months ago

a m=1.50 kg block attached to a massless spring (k=1400N/m). The block is pulled to a position 5.00 cm to the left of its equilibrium?

a m=1.50 kg block attached to a massless spring (k=1400N/m). The block is pulled to a position 5.00 cm to the left of its equilibrium position and released from rest to move on a horizontal frictionless surface. what is the speed of the block when it is 2.00 cm to the right of its equilibrium position?

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  • 11 months ago
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    ...

    energy is conserved

    PE max = PE at 2cm + KE at 2cm

    1/2(1400)(0.0500^2) = 1/2(1400)(0.0200^2) + 1/2 (1.50) v^2

    1/2 's cancel

    3.5 = 0.56 + 1.50 v^2

    1.50 ^2 = 2.94

    v^2 = 1.96

    v = 1.4 m/s

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