Anonymous
Anonymous asked in Science & MathematicsMathematics · 9 months ago

Given the transformation (x,y)→(x, 2x + y) determine the equation of the line 3x + 5y -30 = 0 after it undergoes this transformation.?

3 Answers

Relevance
  • MyRank
    Lv 6
    9 months ago

    (x, y) → (X, 2X + Y)

    3x + 5y - 30 = 0

    3(X) + 5 (2X + Y) - 30 = 0

    3X + 10X+ 5Y - 30 = 0

    13X + 5Y - 30 = 0

    Now transferred equation 13X + 5Y - 30 = 0

  • alex
    Lv 7
    9 months ago

    x' = x

    y'=2x+y=2x'+y --->y=y'-2x'

    replace x,y into 3x + 5y -30 = 0 ---> 3x'+5(y'-2x')-30=0 or -7x'+5y'-30=0

    or

    7x-5y+30=0

  • Ian H
    Lv 7
    9 months ago

    That line is y = 6 – (3/5)x

    A point on that line is therefore [x, 6 – (3/5)x]

    In the transformation x →x, but,

    y→ (2x + y) = 2x + 6 – (3/5)x = (7/5)x + 6

    A point on the new line is therefore [x, (7/5)x + 6]

    The equation of the new line is y = (7/5)x + 6, or,

    5y – 7x – 30 = 0

Still have questions? Get your answers by asking now.