Light asked in Science & MathematicsMathematics · 10 months ago

# trigonometric equation?

ignore whatever is written with pencil. its question 8. If you have time, can you do 8.1 to 8.8 except 8.2 because i have done it.

I know I'm getting too ahead of myself for asking too much to a stranger but i really need to know to do this before exam.

pls ONLY USE COS, SIN and TAN.

Update:

8.1) x=11pi/30 and pi/30

8.3) pi/2 and 3pi/4

i have already got the answers, i need to know how to do it.

Relevance
• 10 months ago

8.1: cos(x - pi/5) = sqrt(3)/2 =>

x - pi/5 = pi/6 or -pi/6

x = pi/5 + pi/6 or pi/5 - pi/6

= 11pi/30 or 1pi/30.

8.3: 2*sin(x)*cos(x) + 2*cos^2(x) = 0 =>

either cos(x) = 0 or sin(x) = -cos(x) =>

x = 0 or x = 3pi/4 or x = 7pi/4.

8.5: 3[2*cos^2(x) - 1] + 5*cos(x) - 1 = 0 =>

6*cos^2(x) + 5*cos(x) - 4 = 0 =>

[3*cos(x) + 4]*[2*cos(x) - 1] = 0 =>

cos(x) = 1/2, because it can't be -4/3.

So x = pi/3 or 5pi/3.

8.7: sin(x)cos(pi/6) + cos(x)*sin(pi/6) = 2*cos(x)cos(pi/3) + 2*sin(x)*sin(pi/3)

=>

sin(x)*sqrt(3)/2 + (1/2)*cos(x) = 1*cos(x) + sqrt(3)*sin(x) =>

-(1/2)*cos(x) = sin(x)*sqrt(3)/2 =>

sin(x)/cos(x) = -1/sqrt(3) =>

tan(x) = -1/sqrt(3) =>

x = 5pi/6 or 11pi/6.