# At a certain temperature, the Kp for the decomposition of H2S is 0.814 atm. EASY 10 PTS?

H2S (g) yields H2(g) + S(g)
Initially, only H2S is present at a pressure of 0.271 atm in a closed container. What is the total pressure in the container at equilibrium?
I am having trouble setting up the first part
I set it up as 0.814=(x)(x)/0.271-x and I know I have to rearrange to solve it as a quadratic,...
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H2S (g) yields H2(g) + S(g)

Initially, only H2S is present at a pressure of 0.271 atm in a closed container. What is the total pressure in the container at equilibrium?

I am having trouble setting up the first part

I set it up as 0.814=(x)(x)/0.271-x and I know I have to rearrange to solve it as a quadratic, but how do I get c for the formula?

Thanks

Initially, only H2S is present at a pressure of 0.271 atm in a closed container. What is the total pressure in the container at equilibrium?

I am having trouble setting up the first part

I set it up as 0.814=(x)(x)/0.271-x and I know I have to rearrange to solve it as a quadratic, but how do I get c for the formula?

Thanks

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