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# If 90.5 moles of an ideal gas is at 1.77 atm at 34.80 °C, what is the volume of the gas?

### 3 Answers

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- electron1Lv 79 months ago
To solve this problem, the temperature must be in ˚K.

T = 34.80 + 273 = 307.8˚K

Let’s use the following equation

P * V = n * R * T

R = 22.4 ÷ 173

1.77 * V = 90.5 * (22.4 ÷ 273) * 307.8

V * 483.21 = 623,772.16

V = 623,772.16 ÷ 483.21

The volume is approximately 1,300 liters.

- pisgahchemistLv 79 months ago
Ideal gas equation ....

"Plug and chug." Solve the ideal gas equation for "V", then plug in the numbers, turn the crank, and out pops the answer.

PV = nRT

V = nRT / P

V = 90.5 mol x 0.08206 Latm/molK x (273.15 + 34.80)K / 1.77 atm

V = 1290L

The answer can only be expressed to three significant digits.

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