A nichrome wire with a resistance of 15.5 is connected across the terminals of a 3.0 V flashlight battery. How much current is in the wire?

2 Answers

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  • MyRank
    Lv 6
    9 months ago
    Best Answer

    Given,

    Resistance (R) = 15.5Ω

    Voltage (V) = 3V

    Current (I) = ?

    We know that:

    Voltage (V) = current (I) x Resistance (R)

    Current (I) = voltage (V) / Resistance (R) = 3V/15.5Ω = 0.19Ω

    ∴ Current (I) = 0.19A.

  • alex
    Lv 7
    9 months ago

    V = RI

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