please solve and i will award best answer?
A jet of water squirts out horizontally from a
hole on the side of the tank as shown below.If the hole has a diameter of 3.51 mm , what
is the height of the water above the hole in
Answer in units of cm.
height is 1.78 m
distance is .6 m
- NCSLv 712 months agoFavorite Answer
Assuming your update applies to the spouting water, then the time it takes to fall is
t = √(2s / g) = √(2 * 1.78m / 9.8m/s²) = 0.60 s
and so the horizontal velocity is
v = x / t = 0.6m / 0.60s = 1.0 m/s
For the height above the hole,
v² = 2gh
h = v² / 2g = (1.0m/s)² / 19.6m/s² = 0.051 m = 5.1 cm
Hope this helps!
- sojsailLv 712 months ago
I am puzzled about the update. Is that the answer?
- Anonymous12 months ago
"shown below"...it must be under water...CAUSE WE DON'T SEE NOTHING!