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# If 5^(b-1) = 2, what is 5^(b+1)?

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- rotchmLv 711 months agoBest Answer
5^(b-1) = 2. Multiply by 5^2 each side to get

5^(b-1)*5^2 = 2 * 5^2. Simplify LHS to get

5^(b-1 + 2) = 2 * 5^2

5^(b+1) = 2 * 5^2

U can compute the RHS. And, see why I multiplied by 5^2 at the beginning?

Done!

- JohnathanLv 711 months ago
5^(b + 1) = 5^(b - 1 + 2) = 5^(b - 1) * 5^2.

Since 5^(b - 1) = 2, 5^(b + 1) = 2 * 5^2 = 50.

- Anonymous11 months ago
-2

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