Anonymous
Anonymous asked in Science & MathematicsMathematics · 11 months ago

If 5^(b-1) = 2, what is 5^(b+1)?

4 Answers

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  • rotchm
    Lv 7
    11 months ago
    Best Answer

    5^(b-1) = 2. Multiply by 5^2 each side to get

    5^(b-1)*5^2 = 2 * 5^2. Simplify LHS to get

    5^(b-1 + 2) = 2 * 5^2

    5^(b+1) = 2 * 5^2

    U can compute the RHS. And, see why I multiplied by 5^2 at the beginning?

    Done!

  • 11 months ago

    5^(b + 1) = 5^(b - 1 + 2) = 5^(b - 1) * 5^2.

    Since 5^(b - 1) = 2, 5^(b + 1) = 2 * 5^2 = 50.

  • Mike G
    Lv 7
    11 months ago

    b+1 = b-1+2

    ∴ 5^(b+1) = 5^(b-1+2)

    = 5^(b-1) * 5^2

    = 2 * 25

    = 50

  • Anonymous
    11 months ago

    -2

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