Anonymous
Anonymous asked in Science & MathematicsPhysics · 11 months ago

If the string is released at the instant the ball is at the top of the loop, how far to the right does the ball hit the ground? PLEASE HELP?

I will award best answer!

A 60 g ball is tied to the end of a 60 -cm-long string and swung in a vertical circle. The center of the circle, as shown in the figure,(Figure 1) is 150 cm above the floor. The ball is swung at the minimum speed necessary to make it over the top without the string going slack.

Thank you!

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2 Answers

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  • oubaas
    Lv 7
    11 months ago
    Best Answer

    g = V^2/r

    V = √r*g = √9.806*0.6 = 2.426 m/sec

    falling time t = √2(1.5+0.6)/9.806 = 0.654 sec

    distance d = V*t = 2.426*0.654 = 1.59 m

  • John P
    Lv 7
    11 months ago

    If you cannot work out the answer yourself, how will you know which is the Best Answer?

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