Pre-cal 12 question pH = -log[H3O+] Therefore, [H3O+]=?

Exponents and Logarithms question help? Where “log” is the logarithm function (you can find it on your calculator). Find the [H3O+] given the pH, so we will need to solve this equation for [H3O+] in terms of pH. Use the following space to do so: pH = -log[H3O+] show steps, please! Therefore, [H3O+]= show... show more Exponents and Logarithms question help?

Where “log” is the logarithm function (you can find it on your calculator). Find the [H3O+] given the pH, so we will need to solve this equation for [H3O+] in terms of pH. Use the following space to do so:
pH = -log[H3O+]

show steps, please!


Therefore, [H3O+]=
show steps, please!
1 answer 1