# Pre-cal 12 question pH = -log[H3O+] Therefore, [H3O+]=?

Exponents and Logarithms question help?
Where “log” is the logarithm function (you can find it on your calculator). Find the [H3O+] given the pH, so we will need to solve this equation for [H3O+] in terms of pH. Use the following space to do so:
pH = -log[H3O+]
show steps, please!
Therefore, [H3O+]=
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Exponents and Logarithms question help?

Where “log” is the logarithm function (you can find it on your calculator). Find the [H3O+] given the pH, so we will need to solve this equation for [H3O+] in terms of pH. Use the following space to do so:

pH = -log[H3O+]

show steps, please!

Therefore, [H3O+]=

show steps, please!

Where “log” is the logarithm function (you can find it on your calculator). Find the [H3O+] given the pH, so we will need to solve this equation for [H3O+] in terms of pH. Use the following space to do so:

pH = -log[H3O+]

show steps, please!

Therefore, [H3O+]=

show steps, please!

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