What is the pressure in a 23.0-L cylinder filled with 44.1 g of oxygen gas at a temperature of 327 K?

Please explain how you got the answer. Thank you.

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  • 2 years ago
    Favorite Answer

    Use the Ideal Gas Equation

    PV = nRT

    P ; to be found

    V = 23.0 L = 0.023 m^3

    n = moles O2 = 441./32 = 1.378125 moles

    R = the gas constant 8.314

    T 327 K

    Substituting in

    P = nRT/V

    P = 1.378125 x 8.314 x 327 / 0.023

    P = 162,899.049 Pa

    P = 1.607 atms.

  • 2 years ago

    Use the gas equation:

    PV = nRT

    P = pressure = ?

    V = volume = 23.0L

    n = moles O2 = 44.1g/32g/mol = 1.378 mol

    R = gas constant = 0.082057

    T = temperature = 327K

    Substitute and solve for P

    P*23.0 = 1.378*0.082057*327

    P = 1.378*0.082057*327/ 23.0

    P = 1.6077atm

    Answer: Pressure = 1.61 atm

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