The first step is to write the balanced equation for this reaction. The products are carbon dioxide and water.
C3H8 + O2 → CO2 + H2O
To balance the C’s, make 3 CO2. To balance the H’s, make 4 H2O.
C3H8 + O2 → 3 CO2 + 4 H2O
To balance the O’s, make 5 O2.
C3H8 + 5 O2 → 3 CO2 + 4 H2O
Since we have excess oxygen, all of the propane will burn. According to the coefficients in this equation, one mole of propane will produce four moles of water. The next step is to calculate the mass of one mole of propane.
Mass = 12 * 3 + 8 = 44 grams
To determine the number of moles of propane, divide the mass of propane by this number.
n = 447.87 ÷ 44
This is approximately 10.1 moles. Each mole of propane contains four moles of water.
For water, n = 447.84 ÷ 11
This is approximately 40.4 moles of water. The mass of one mole of water is 18 grams.
Mass H2O = 18 * 447.84 ÷ 11
This is approximately 728 grams of water. I hope this is helpful for you.