For the reaction Cl2 + 2KBr → 2KCl + Br2, how many moles of potassium chloride are produced from 321.6 g of potassium bromide?
- 2 years ago
First, you want to convert the potassium bromide to mol.
Its molar mass is M = K (39.1) + Br (79.9) = 119 g/mol
Then g / M = 321.6 / 119 = 2.703 mol
Now we look at the equation: the ratio of potassium bromide to potassium chloride is 1:1
This means for every mol of KBr you put in, you get 1 mol of KCl
Therefore, since you put in 2.703 mol of KBr, you get out 2.703 mol KCl