Anonymous
Anonymous asked in Science & MathematicsChemistry · 2 years ago

P4(s) + 10 F2(g) → 4 PF5(g) How many moles of fluorine gas are required to form 100.0 g of phosphorus pentafluoride?

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  • 2 years ago

    The molar mass of PF5 is 125.966, so 100.0 grams are 0.79386 moles.

    For each mole of PF5 produced, one needs (10/4) mole of fluorine gas, or 2.5 moles of fluorine gas.

    Therefore the answer to the question is

    (0.79386 moles)*(2.5) = 1.985 moles of fluorine gas.

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