Physics help?

A gas occupies 0.60 m3 at a 5.0 atm. If the temperature of the gas remains the same and the pressure decreases to 2.5 atm, what would be the new volume occupied by the gas?

Please don't just give me an answer! I really need to understand so please walk me through the steps and explain it.

4 Answers

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  • 2 years ago
    Favorite Answer

    If volume go up

    Pressure go down.

    The first equation in kinetic theory is pV = nRT.

    At constant temperature (T), and constant amount of gas (n), we have

    p*V = constant (called Boyle's law)

    Soooo

    If pressure drops to half its original value, then volume must've doubled for their product to remain the same.

    p1 * V1 = 0.5p1 * 2V1

    p2 = 0.5p1 = 2.5 atm

    V2 = 2V1 = 1.2 m^3 answer

  • 2 years ago

    Since the temperature is constant, the volume is inversely proportional to the pressure. You can use the following equation to solve this problem.

    P1 * V1 = P2 * V2

    0.6 * 5 = 2.5 * V2

    V2 = 3 ÷ 2.5 = 1.2 m^3

  • Anonymous
    2 years ago

    You can do it using just ‘common sense’ if you understand what is going on.

    If temperature is the same, then pressure x volume = constant. This is called Boyle's law.

    So when pressure is halved, the volume is must be doubled (so that the value of pressure x volume is unchanged).

    So the new volume = 2 x 0.60 = 1.20m³

  • 2 years ago

    What is this, a game, physics class, or just a comment to let us know how intelligent your are?

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