# Physics help?

A gas occupies 0.60 m3 at a 5.0 atm. If the temperature of the gas remains the same and the pressure decreases to 2.5 atm, what would be the new volume occupied by the gas?

Please don't just give me an answer! I really need to understand so please walk me through the steps and explain it.

### 4 Answers

- RealProLv 72 years agoFavorite Answer
If volume go up

Pressure go down.

The first equation in kinetic theory is pV = nRT.

At constant temperature (T), and constant amount of gas (n), we have

p*V = constant (called Boyle's law)

Soooo

If pressure drops to half its original value, then volume must've doubled for their product to remain the same.

p1 * V1 = 0.5p1 * 2V1

p2 = 0.5p1 = 2.5 atm

V2 = 2V1 = 1.2 m^3 answer

- electron1Lv 72 years ago
Since the temperature is constant, the volume is inversely proportional to the pressure. You can use the following equation to solve this problem.

P1 * V1 = P2 * V2

0.6 * 5 = 2.5 * V2

V2 = 3 ÷ 2.5 = 1.2 m^3

- Anonymous2 years ago
You can do it using just ‘common sense’ if you understand what is going on.

If temperature is the same, then pressure x volume = constant. This is called Boyle's law.

So when pressure is halved, the volume is must be doubled (so that the value of pressure x volume is unchanged).

So the new volume = 2 x 0.60 = 1.20m³

Thank you so much!