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Probability Question?

Your large multinational corporation has retail stores in cities across the country. The average number of employees at each store is 83 with a standard deviation of 10 employees. You ask your assistant to pick 9 stores at random and compute the average number of employees in your sample. Find the approximate probability that your assistant reports an average yield that:

(a) is more than 100 employees

(b) is less than 80 employees

(c) is between 80 and 100 employees

1 Answer

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  • Mike G
    Lv 7
    2 years ago
    Favorite Answer

    μ = 83

    σ = 10

    s = 10/√9 = 10/3 = 3.33

    a) z = (100-83)/3.33 = 5.1

    P(z>5.1) = 0

    b) z = -0.9

    P(z<-0.9) = 0.1841

    c) P(-0.9<z<5.1) = 0.8159

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