Jake asked in Science & MathematicsPhysics · 2 years ago

Fluid dynamics?

An oil with a specific gravity of 0.78 flows at

a velocity of 0.8 m/s in a 2” schedule 40 pipe. Find both

the volume flow rate and the mass flow rat

3 Answers

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  • 2 years ago
    Favorite Answer

    Use the table in this link: https://www.engineeringtoolbox.com/ansi-steel-pipe...

    (about ¼ of the way down, click the blue ‘mm2’ label at the top of the ‘Transverse Areas’ column)

    This gives the internal cross-sectional (transverse) area of 2” schedule 40 pipe as 2168mm², which is 2168x10⁻⁶ m² (as 1mm² = 10 ⁶m²).

    The volume flow rate (Rv) is Rv = vA = 0.8 x 2168x10⁻⁶ = 0.0017344 m³/s

    The should be rounded to 2 sig. figs. to match the precision of the supplied data:

    Volume flow rate, Rv = 0.0017m³/s to 2 sig. figs.

    The specific gravity of the oil is 0.78 and the density of water is 1000kg/m³. So the density of the oil is ρ = 0.78 x 1000 = 780kg/m³.

    The mass flow rate (Rm) is Rm = ρRv = 780 x 0.0017344 = 1.353kg/s

    To 2 sig. figs this is 1.4kg/s.

  • oubaas
    Lv 7
    2 years ago

    A ≈ 2170 mm² corresponding to ≈ 0.217 dm^2

    volum. flow Qv = A*V = 0.217 dm^2*8 dm/sec = 1.74 dm^3/sec

    mass flow Qm = 1.74 dm^3/sec*0.80 kg/dm^3 = 1.39 kg/sec

    weight flow Qw =Qm*g = 1.39*9.806 = 13.6 N/sec

  • Jim
    Lv 7
    2 years ago

    Look up in pipe table (online) the O.D. in mm and the schedule 40 pipe wall thickness, then:

    Subtract twice the wall thickness from the O.D. to get the I.D. of schd 40 pipe. This should be = ID = 52.506 mm

    Calculate area of pipe in base SI units = π(ID)²/4 = 2165.25E-6 m²

    Volume rate of flow = 0.8(2165.25E-6) = 1732.20E-6 ≈ 1730E-6 m³/s ANS

    Mass rate of flow = (0.78)(1000)(1732.20E-6) = 135.11 ≈ 135 kg/s ANS

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