How to make a .5 mL solution with the following chemicals?

0.2 M LiOAc (stock solution is 1 M) 40 percent PEG 3500 (stock solution is 50 percent) .1 M DTT (stock solution is 1 M) When I did the calculations, I got .4 mL of 50 percent PEG needed, .1 mL of 1M LiOAc needed, and .05 mL of 1M DTT needed, which adds up to .55 mL when the solution should be .5 mL. We don't... show more 0.2 M LiOAc (stock solution is 1 M)
40 percent PEG 3500 (stock solution is 50 percent)
.1 M DTT (stock solution is 1 M)

When I did the calculations, I got .4 mL of 50 percent PEG needed, .1 mL of 1M LiOAc needed, and .05 mL of 1M DTT needed, which adds up to .55 mL when the solution should be .5 mL.

We don't have stock solutions of higher concentrations in the lab, so I'm just a little confused as to how I'm supposed to make this buffer. Did I do my calculations wrong? Is there a way to make this without needing solutions with higher concentrations?
1 answer 1