16.) A student walks 60 m west and 90 m south.?

B.) What is the magnitude of the displacement that will bring the student back to the starting point?

Express your answer using two significant figures.

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  • 3 years ago
    Favorite Answer

    It's a right triangle

    d = √(60² + 90²) = 108 m

    rounded to 110 m

  • 3 years ago

    A student walks 60 m west from point A to point B ( on horizontal axis x,x ) and from point B to point C by walking down vertically on y,y axis with a distance of 90 m to a point C where we need to find distance CA .

    when we connect point ABC it wouldmake a right angle triangle ABC where angle ABC is making 90 degree angle .

    In this triangle , we need to find distance CA with applying pythagorus theory of right trianglle.

    so , CA = SQ ROOT of ( AB2 + BC2 ) = SQ ROOT ( 60^2 + 90 ^2 ) = SQ ROOT of ( 3600 + 8100 ) = (11700)^1/2 m = 96 m

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