16.) A student walks 60 m west and 90 m south.?
B.) What is the magnitude of the displacement that will bring the student back to the starting point?
Express your answer using two significant figures.
- billrussell42Lv 73 years agoFavorite Answer
It's a right triangle
d = √(60² + 90²) = 108 m
rounded to 110 m
- Mr.MukherjeeLv 63 years ago
A student walks 60 m west from point A to point B ( on horizontal axis x,x ) and from point B to point C by walking down vertically on y,y axis with a distance of 90 m to a point C where we need to find distance CA .
when we connect point ABC it wouldmake a right angle triangle ABC where angle ABC is making 90 degree angle .
In this triangle , we need to find distance CA with applying pythagorus theory of right trianglle.
so , CA = SQ ROOT of ( AB2 + BC2 ) = SQ ROOT ( 60^2 + 90 ^2 ) = SQ ROOT of ( 3600 + 8100 ) = (11700)^1/2 m = 96 m