# How to solve the following expression algebraically: (x+y)^-2 = x^-2(1+y/x)^-2 Thanks.?

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- BrainardLv 72 years agoBest Answer
Your expression is an identity and not an equation

LHS = (x + y)^-2

= 1/(x + y)^2

= 1/[ x(1 + y/x)]^2

= 1/x^2(1 + y/x)^2

= x^-2(1 + y/x)^-2

= RHS

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