A 30 g ball rolls around a 42 cm diameter L-shaped track, shown in the figure below, at 60 rpm. Rolling friction can be neglected.?
What is the magnitude of the net force on the ball?
- Anonymous3 years agoFavorite Answer
42cm.diameter = 0.21m. radius, and 30g = 0.030kg.
(60/60s) = 1rps.
(1 x 2pi) = 6.2832 rad/sec.
V = (6.2832 x 0.21m. radius) = 1.3195 m/sec.
Force = (m*v^2)/r = (0.03 x 1.3195^2)/0.21 = 0.2487N.
- Anonymous3 years ago
It goes 19mph