Anonymous
Anonymous asked in Science & MathematicsPhysics · 3 years ago

A 30 g ball rolls around a 42 cm diameter L-shaped track, shown in the figure below, at 60 rpm. Rolling friction can be neglected.?

What is the magnitude of the net force on the ball?

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  • Anonymous
    3 years ago
    Favorite Answer

    42cm.diameter = 0.21m. radius, and 30g = 0.030kg.

    (60/60s) = 1rps.

    (1 x 2pi) = 6.2832 rad/sec.

    V = (6.2832 x 0.21m. radius) = 1.3195 m/sec.

    Force = (m*v^2)/r = (0.03 x 1.3195^2)/0.21 = 0.2487N.

  • Anonymous
    3 years ago

    It goes 19mph

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