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# Prove math 10 points?

1. (cos2B+cos2A)/(cos2B-cos2A)=cot(A+B)cot(A-B)

2. (cos2B-cos2A)/(sin2B+sin2A)=tan(A-B)

3. (sinA+2sin3A+sin5A)/(sin3A+2sin5A+sin7A)=sin3A/sin5A

Sorry there is technical prbm

here is:

1. = cot (A+B)cot(A-B)

3. =sin3A/sin5A

tq so much for helping!!!

### 1 Answer

- Snugglebunnie101Lv 52 years agoFavorite Answer
OK, here you go sweetheart :)

The first two questions are relatively straightforward!

1) Prove (cos2B+cos2A)/(cos2B-cos2A) = cot(A+B)cot(A-B)

Use the sum - product trig identities to obtain:

cos2B + cos2A = 2cos(A + B)cos(A - B)

cos2B - cos2A = 2sin(B + A)sin(A - B)

LHS = [2cos(A + B)cos(A - B)] /[2sin(B + A)sin(A - B)]

= cot(A + B)cot(A - B)

= RHS, as required!

2) Prove (cos2B - cos2A)/(sin2B+sin2A) = tan(A-B)

Again, using the same steps as above we have the left - hand side as :

cos2B - cos2A = 2sin(B + A)sin(A - B)

sin2B + sin2A = 2sin(B + A)sin(A - B)

LHS = [2sin(B + A)sin(A - B)] /[2sin(B + A)sin(A - B)]

= sin(A - B) /cos(A - B)

= tan(A - B)

= RHS, as required!

3) Now for this question, please consult the following resource (I don't have enough space on here to write my own solution!)

https://answers.yahoo.com/question/index?qid=20120...

Hope this helps !!!!!!!!!!!!!!!!!!!!!!!!

Tqvm!!!!!!!!