Hot tea and ice?

Given 100 g of hot tea at 90°C, what mass of ice at –10°C must be added in order to obtain a final temperature of 10°C? specific heat of ice = 2.09 J/g°C specific heat of tea = specific heat of liquid water = 4.18 J/g°C normal freezing point of water = 0°C normal boiling point of water = 100°C ∆H° = +6.01... show more Given 100 g of hot tea at 90°C, what mass of ice at –10°C must be added in order to obtain a final temperature of 10°C?

specific heat of ice = 2.09 J/g°C
specific heat of tea = specific heat of liquid water = 4.18 J/g°C
normal freezing point of water = 0°C normal boiling point of water = 100°C
∆H° = +6.01 kJ/mol for the melting of ice:H2O (s) →H2O (l)
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