Bob Beamon's record breaking long jump (8.9m)?

Question

(continuation for the question) in the 1968 olympics resulted from an initial velocity of 9.5m/s at an angle 40 degree to the horizontal. Compute for Vix, Viy , time total, horizontal distance(range) and height.

Answer 1

(cos 40 x 9.5) = Vix of 7.28m/sec.

(sin 40 x 9.5) = Viy of 6.1m/sec.

Total time in air = 2(v/g) = 2(Viy/9.8) = 1.24 secs.

Range = (1.24 x Vix) = 9.03 metres?