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# Calculate the volume of 6.29 mol O2 gas at 30.0 cm Hg and 72.0 degrees F?

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- pisgahchemistLv 73 years agoFavorite Answer
Gas law problem....

PV = nRT ............... ideal gas equation

V = nRT / P ............ solve for V

V = 6.29 mol x 62.36 Ltorr/molK x 295.4K / 30.0 torr

V = 3860 L ............. rounded to three significant digits

F = 1.8C + 32 ..... and ..... C = (F-32)/1.8

K = C + 273

The units of "torr" have replaced "millimeters of mercury", but the two are interchangeable. Standard pressure = 760 torr ... or ... 760 mm Hg

Use the value of R which corresponds to the units of pressure

R = 8.314 LkPa/molK ................ P in kilopascals

R = 0.08206 Latm/molK ............ P in atmospheres

R = 62.36 Ltorr/molK ................. P in torr

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