sah asked in Science & MathematicsPhysics · 3 years ago

the 7kg blockis beging acelerated from 4m/s to 12m/s in 5.0s if the coefficient of sliding friction is 0.5?

the 7kg blockis beging acelerated from 4m/s to 12m/s in 5.0s if the coefficient of sliding friction is 0.5 calculated the weing and normal forces and calculated the friction and applied force

Update:

doy estrellas

1 Answer

Relevance
  • Anonymous
    3 years ago
    Best Answer

    Change in V = (12 - 4) = 8m/sec., in 5 secs.

    Acceleration = (v/t) = (8/5) = 1.6m/sec^2.

    If there were no friction, the force required to accelerate at 1.6m/sec^2 = (ma) = (7 x 1.6) = 11.2N.

    Normal force = (mg) = (7 x 9.8) = 68.6N. (ans).

    The normal force upwards, is equal to weight downwards. Is "weing" meant to be weight?

    Friction force = (68.6 x 0.5) = 34.3N. (ans)

    You need to apply (11.2 + 34.3) = 45.5N. (ans).

Still have questions? Get your answers by asking now.