the 7kg blockis beging acelerated from 4m/s to 12m/s in 5.0s if the coefficient of sliding friction is 0.5?
the 7kg blockis beging acelerated from 4m/s to 12m/s in 5.0s if the coefficient of sliding friction is 0.5 calculated the weing and normal forces and calculated the friction and applied force
- Anonymous3 years agoBest Answer
Change in V = (12 - 4) = 8m/sec., in 5 secs.
Acceleration = (v/t) = (8/5) = 1.6m/sec^2.
If there were no friction, the force required to accelerate at 1.6m/sec^2 = (ma) = (7 x 1.6) = 11.2N.
Normal force = (mg) = (7 x 9.8) = 68.6N. (ans).
The normal force upwards, is equal to weight downwards. Is "weing" meant to be weight?
Friction force = (68.6 x 0.5) = 34.3N. (ans)
You need to apply (11.2 + 34.3) = 45.5N. (ans).