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physics projectile motion problem?
John releases an oil filled ball outside his apartment window and notices his friend 224ft below on the stoop directly under the balls path. 2s after the ball is released, his friend launches a dart directly upward at 64ft/s towards the ball.
1.) how much time elapses between the darts release and the dart puncturing the ball?
2.) assuming the ball bursts instantaneously, how much time does John have to evade the mess?
- ?Lv 64 years agoFavorite Answer
1) Set up two distances.
Distance ball: d₁ = ½g(t+2)²
Distance dart: d₂ = 64t − ½gt²
g = 32.2 ft/s²
d₁ + d₂ = 224 ft
½g(t²+4t+4) + 64t − ½gt² = 224 ft
t = (224−2g)/(64+2g) = 1.24 s
2) Total time for the oil: t = √(2h/g) = √(448/g) = 3.73 s
3.73s−2s−1.24s = 0.49 s