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# 6.4 calc problem?

A spring has natural length 20 cm. Compare the work W1 done in stretching the spring from 20 cm to 30 cm with the work W2 done in stretching it from 30 to 40 cm. (Use k for the spring constant) W1 = W2 = How are W2 and W1 related?

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- JimLv 74 years agoFavorite Answer
SPE = 1/2kx² {where x = extended length in cm - 20}

W1 = SPE(30) - SPE(20) = (k/2)[(30-20)² - (20-20)²] = k/2(100) = 50k

W2 = SPE(40) - SPE(30) = (k/2)[(40-20)² - (30-20)²] = k/2(400 - 100) = 150k

W2/W1 = 150k/50k = 3 ANS

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only the last answer was correct. E for Effort! :)