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A 1100 kg safe is 2.0 m above a heavy-duty spring when the rope holding the safe breaks. The safe hits the spring and compresses it 40 cm. What is the spring constant of the spring?

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  • Jim
    Lv 7
    4 years ago
    Favorite Answer

    max GPE of safe {reference height 2.0 m: i.e. at top of spring} = mgh = 1100(9.81)(2) = 21,582 J

    max GPE of safe {reference height 2.4 m} = 21,582 + (1100)(9.81)(0.40) = 25,898.4 J

    max SPE = 1/2kx² = 25,898.4 {where x = 0.40 m}

    k = 51,796.8/(0.40)² = 323,730 ≈ 324,000 N/m ANS

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