Anonymous
Anonymous asked in Science & MathematicsPhysics · 4 years ago

A 350. g cart is launched up a ramp by a spring with a spring constant of 170.0 N/m that is compressed 11.0 cm. If the track is inclined at?

Update:

a 15.0 degree angle to the horizontal, calculate the height it reaches above its start, and the distance it travels up the ramp.

I know the answers (h = .300 m; d = 1.16 m), but can't formulate the work to write out

1 Answer

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  • Jim
    Lv 7
    4 years ago
    Favorite Answer

    Max SPE {Max Spring Potential Energy} = 1/2kx² = (0.5)(170)(0.11)² = 1.0285 J

    Max GPE of cart = 1.0285 = mgh = 0.350(9.81)h = 3.4335h {h = vertical height of cart on incline}

    3.4335h = 1.0285

    h = 0.29955 ≈ 0.300 m ANS

    d = distance along incline that cart travels = h/sin Θ = h/sin 15° = 0.29955/sin 15° = 1.1574 ≈ 1.16 m ANS

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