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# A 300.0 cm long spring is compressed with a force of 5.00 N, then it is compressed 4.00 cm with a force of 10.0 N, and finally it is compres?

Update:

sed 6.00 cm with a force of 15.0 N. Calculate the force required to compress it 112 cm (Fs), and the energy contained in the spring when it is released (Ee)

I know both answers, just am struggling with how to find out how to do the work

Update 2:

The answers are 280 N, and 160 J

### 1 Answer

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- JimLv 74 years agoFavorite Answer
k of spring = F/x = 10/4 = 2.5 = 15/6 = 2.5 = F/112 = 2.5 N/cm = 2.5 N/0.01 m = 250 N/m

F = 2.5(112) = 280 N ANS

SPE when compressed 1.12 m = 1/2kx² = (0.5)(250)x² = 125x² {where x is in m}

SPE = 125(1.12)² = 156.8 ≈ 157 ≈ 160 J ANS*

*Note: the SPE formula REQUIRES that BASE units be used. That is, the k MUST be in "N/m", and the x distance MUST be in meters. However in the spring force equation {F = kx} that is not the case. Ask UR teacher, why...?

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