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# rotation motion?

A rigid body is initially at rest. At time t = 0, it is given a constant angular acceleration of 0.060 rad/s2. Find the magnitude of the centripetal acceleration of a point that is a distance of 2.5 m from the axis of rotation at t = 8.0 s

### 1 Answer

- ?Lv 76 years agoFavorite Answer
Ac = Centripetal acceleration = w²R {where R = 2.5 m}

w = α•t = 0.060(8.0) = 0.48 rad/s

Ac = (0.48)²(2.5) = ___________ m/s² {U got a calculator handy?}