maximum distance spring will be compressed?

could anyone show me how to solve this? Thank you!

http://imgur.com/ire4k6O

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1 Answer

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  • Jim
    Lv 7
    4 years ago
    Favorite Answer

    Initial GPE of mass above spring/plate = mgh = 2(9.8)(0.48) = 9.408 J

    9.408 J = max SPE of spring/plate + GPE of spring/plate compression = 1/2kx² + mgx

    1/2kx² = (0.5)1600x² = 800x²

    mgx = 2(9.8)x = 19.6x

    9.408 = 800x² + 19.6x

    0 = 800x² + 19.6x - 9.408

    solve quadratic for positive x:

    x = 0.09688 = 9.7 cm ANS

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