maximum distance spring will be compressed?
could anyone show me how to solve this? Thank you!
- JimLv 74 years agoFavorite Answer
Initial GPE of mass above spring/plate = mgh = 2(9.8)(0.48) = 9.408 J
9.408 J = max SPE of spring/plate + GPE of spring/plate compression = 1/2kx² + mgx
1/2kx² = (0.5)1600x² = 800x²
mgx = 2(9.8)x = 19.6x
9.408 = 800x² + 19.6x
0 = 800x² + 19.6x - 9.408
solve quadratic for positive x:
x = 0.09688 = 9.7 cm ANS