Can anyone help me solve these?

a) 3π‘₯ + 3(π‘₯ βˆ’ 7) = 5π‘₯ + 22

What is x?

b) 5π‘₯ + 3π‘₯(124 βˆ’ (62 + 62)) = 0 ?

c) 2 + 7π‘₯ = 7π‘Ž + 2?

3 Answers

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  • 5 years ago

    a)

    3π‘₯ + 3(π‘₯ βˆ’ 7) = 5π‘₯ + 22

    x = π‘₯ = 43

    b)

    5π‘₯ + 3π‘₯(124 βˆ’ (62 + 62)) = 0

    x = π‘₯ = 0

    c)

    2 + 7π‘₯ = 7π‘Ž + 2

    True

  • david
    Lv 7
    5 years ago

    a) x = 43

    b) x = 0

    c) x = a

  • 5 years ago

    (a) 6x - 21 = 5x + 22 => x = 43.

    (b) 5x + 3x(0) = 0 => x = 0.

    (c) 2 + 7x = 7a + 2 => x = a.

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