1991 World Track and Field Championships in Tokyo, Mike Powell jumped 8.95 m, breaking long-jump record set by Bob Beamon in Mexico City.?

Assuming that g=9.80 m/s/s in Tokyo, what is the slowest possible launch-speed that would allow Beamon to travel that distance?

2 Answers

  • Steve
    Lv 5
    6 years ago

    Cannot be determined from given data. We don't know the speed and direction of wind and air resistance. A man is not a cannon ball. The equations of projectile motion refer to the center of mass of an object. Long jump is measured where the foot takes off and land. The foot is not the center of mass of the body.

  • 6 years ago


    g = 9.80 m/s²

    θ = 45°

    R = horizontal range = 8.95 m

    v = jump velocity = to be determined

    R = v²∙sin 2θ /g

    Rg = v²∙sin 2θ

    Rg / sin 2θ = v²

    v² = Rg / sin 2θ

    v = √(Rg / sin 2θ)

    v = √[(8.95 m )(9.80 m/s²) / sin 2∙45°]

    v = 9.37 m/s

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