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# Maths - Area

A rectangle with width x cm. and length 2x cm. is to be inscribed in a right - angled triangle with hypotenus = 18cm. Find the largest possible value of x.

Update:

To : pui How can a 8.05 cm. x 16.1 cm. rectangle be inscribed in a triangle with hypotenus 18 cm. ??

### 2 Answers

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- 5 years agoFavorite Answer
x^2 + (2x)^2 =18^2

5x^2=324

x^2=64.8

x=8.05 cm

2015-07-26 10:50:48 補充：

If ABCD is a rectangle. AB of width is x cm. CD of length 2x cm. AC=BD=hypotenuse= 18cm. There are 2 right triangle to a rectangle.

According to the Pythagorean theorem,

AB^2 +CD^2 =AC^2

x^2 +(2x)^2 =18^2

x^2 +4x^2=324

5x^2=324

x^2=64.8

x is nearly 8.05cm

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