Anonymous
Anonymous asked in 科學及數學數學 · 5 years ago

Maths - Area

A rectangle with width x cm. and length 2x cm. is to be inscribed in a right - angled triangle with hypotenus = 18cm. Find the largest possible value of x.

Update:

To : pui How can a 8.05 cm. x 16.1 cm. rectangle be inscribed in a triangle with hypotenus 18 cm. ??

2 Answers

Rating
  • 5 years ago
    Favorite Answer

    x^2 + (2x)^2 =18^2

    5x^2=324

    x^2=64.8

    x=8.05 cm

    2015-07-26 10:50:48 補充:

    If ABCD is a rectangle. AB of width is x cm. CD of length 2x cm. AC=BD=hypotenuse= 18cm. There are 2 right triangle to a rectangle.

    According to the Pythagorean theorem,

    AB^2 +CD^2 =AC^2

    x^2 +(2x)^2 =18^2

    x^2 +4x^2=324

    5x^2=324

    x^2=64.8

    x is nearly 8.05cm

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  • 5 years ago

    我計到 x = (36√5)/25

    請問是否正確?

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